Integrand size = 28, antiderivative size = 194 \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{3/2}}{(d+e x)^4} \, dx=\frac {(b d-a e)^3 \sqrt {a^2+2 a b x+b^2 x^2}}{3 e^4 (a+b x) (d+e x)^3}-\frac {3 b (b d-a e)^2 \sqrt {a^2+2 a b x+b^2 x^2}}{2 e^4 (a+b x) (d+e x)^2}+\frac {3 b^2 (b d-a e) \sqrt {a^2+2 a b x+b^2 x^2}}{e^4 (a+b x) (d+e x)}+\frac {b^3 \sqrt {a^2+2 a b x+b^2 x^2} \log (d+e x)}{e^4 (a+b x)} \]
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Time = 0.06 (sec) , antiderivative size = 194, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {660, 45} \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{3/2}}{(d+e x)^4} \, dx=\frac {3 b^2 \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)}{e^4 (a+b x) (d+e x)}-\frac {3 b \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^2}{2 e^4 (a+b x) (d+e x)^2}+\frac {\sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^3}{3 e^4 (a+b x) (d+e x)^3}+\frac {b^3 \sqrt {a^2+2 a b x+b^2 x^2} \log (d+e x)}{e^4 (a+b x)} \]
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Rule 45
Rule 660
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {a^2+2 a b x+b^2 x^2} \int \frac {\left (a b+b^2 x\right )^3}{(d+e x)^4} \, dx}{b^2 \left (a b+b^2 x\right )} \\ & = \frac {\sqrt {a^2+2 a b x+b^2 x^2} \int \left (-\frac {b^3 (b d-a e)^3}{e^3 (d+e x)^4}+\frac {3 b^4 (b d-a e)^2}{e^3 (d+e x)^3}-\frac {3 b^5 (b d-a e)}{e^3 (d+e x)^2}+\frac {b^6}{e^3 (d+e x)}\right ) \, dx}{b^2 \left (a b+b^2 x\right )} \\ & = \frac {(b d-a e)^3 \sqrt {a^2+2 a b x+b^2 x^2}}{3 e^4 (a+b x) (d+e x)^3}-\frac {3 b (b d-a e)^2 \sqrt {a^2+2 a b x+b^2 x^2}}{2 e^4 (a+b x) (d+e x)^2}+\frac {3 b^2 (b d-a e) \sqrt {a^2+2 a b x+b^2 x^2}}{e^4 (a+b x) (d+e x)}+\frac {b^3 \sqrt {a^2+2 a b x+b^2 x^2} \log (d+e x)}{e^4 (a+b x)} \\ \end{align*}
Time = 1.06 (sec) , antiderivative size = 104, normalized size of antiderivative = 0.54 \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{3/2}}{(d+e x)^4} \, dx=\frac {\sqrt {(a+b x)^2} \left ((b d-a e) \left (2 a^2 e^2+a b e (5 d+9 e x)+b^2 \left (11 d^2+27 d e x+18 e^2 x^2\right )\right )+6 b^3 (d+e x)^3 \log (d+e x)\right )}{6 e^4 (a+b x) (d+e x)^3} \]
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Time = 3.07 (sec) , antiderivative size = 146, normalized size of antiderivative = 0.75
method | result | size |
risch | \(\frac {\sqrt {\left (b x +a \right )^{2}}\, \left (-\frac {3 b^{2} \left (a e -b d \right ) x^{2}}{e^{2}}-\frac {3 b \left (a^{2} e^{2}+2 a b d e -3 b^{2} d^{2}\right ) x}{2 e^{3}}-\frac {2 a^{3} e^{3}+3 a^{2} b d \,e^{2}+6 a \,b^{2} d^{2} e -11 b^{3} d^{3}}{6 e^{4}}\right )}{\left (b x +a \right ) \left (e x +d \right )^{3}}+\frac {b^{3} \ln \left (e x +d \right ) \sqrt {\left (b x +a \right )^{2}}}{e^{4} \left (b x +a \right )}\) | \(146\) |
default | \(\frac {\left (\left (b x +a \right )^{2}\right )^{\frac {3}{2}} \left (6 \ln \left (e x +d \right ) b^{3} e^{3} x^{3}+18 \ln \left (e x +d \right ) b^{3} d \,e^{2} x^{2}+18 \ln \left (e x +d \right ) b^{3} d^{2} e x -18 x^{2} a \,b^{2} e^{3}+18 x^{2} b^{3} d \,e^{2}+6 \ln \left (e x +d \right ) b^{3} d^{3}-9 a^{2} b \,e^{3} x -18 x a \,b^{2} d \,e^{2}+27 b^{3} d^{2} e x -2 a^{3} e^{3}-3 a^{2} b d \,e^{2}-6 a \,b^{2} d^{2} e +11 b^{3} d^{3}\right )}{6 \left (b x +a \right )^{3} e^{4} \left (e x +d \right )^{3}}\) | \(186\) |
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Time = 0.32 (sec) , antiderivative size = 177, normalized size of antiderivative = 0.91 \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{3/2}}{(d+e x)^4} \, dx=\frac {11 \, b^{3} d^{3} - 6 \, a b^{2} d^{2} e - 3 \, a^{2} b d e^{2} - 2 \, a^{3} e^{3} + 18 \, {\left (b^{3} d e^{2} - a b^{2} e^{3}\right )} x^{2} + 9 \, {\left (3 \, b^{3} d^{2} e - 2 \, a b^{2} d e^{2} - a^{2} b e^{3}\right )} x + 6 \, {\left (b^{3} e^{3} x^{3} + 3 \, b^{3} d e^{2} x^{2} + 3 \, b^{3} d^{2} e x + b^{3} d^{3}\right )} \log \left (e x + d\right )}{6 \, {\left (e^{7} x^{3} + 3 \, d e^{6} x^{2} + 3 \, d^{2} e^{5} x + d^{3} e^{4}\right )}} \]
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\[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{3/2}}{(d+e x)^4} \, dx=\int \frac {\left (\left (a + b x\right )^{2}\right )^{\frac {3}{2}}}{\left (d + e x\right )^{4}}\, dx \]
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Exception generated. \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{3/2}}{(d+e x)^4} \, dx=\text {Exception raised: ValueError} \]
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Time = 0.27 (sec) , antiderivative size = 179, normalized size of antiderivative = 0.92 \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{3/2}}{(d+e x)^4} \, dx=\frac {b^{3} \log \left ({\left | e x + d \right |}\right ) \mathrm {sgn}\left (b x + a\right )}{e^{4}} + \frac {18 \, {\left (b^{3} d e \mathrm {sgn}\left (b x + a\right ) - a b^{2} e^{2} \mathrm {sgn}\left (b x + a\right )\right )} x^{2} + 9 \, {\left (3 \, b^{3} d^{2} \mathrm {sgn}\left (b x + a\right ) - 2 \, a b^{2} d e \mathrm {sgn}\left (b x + a\right ) - a^{2} b e^{2} \mathrm {sgn}\left (b x + a\right )\right )} x + \frac {11 \, b^{3} d^{3} \mathrm {sgn}\left (b x + a\right ) - 6 \, a b^{2} d^{2} e \mathrm {sgn}\left (b x + a\right ) - 3 \, a^{2} b d e^{2} \mathrm {sgn}\left (b x + a\right ) - 2 \, a^{3} e^{3} \mathrm {sgn}\left (b x + a\right )}{e}}{6 \, {\left (e x + d\right )}^{3} e^{3}} \]
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Timed out. \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{3/2}}{(d+e x)^4} \, dx=\int \frac {{\left (a^2+2\,a\,b\,x+b^2\,x^2\right )}^{3/2}}{{\left (d+e\,x\right )}^4} \,d x \]
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